131112114140003 has 8 divisors (see below), whose sum is σ = 131817945172320. Its totient is φ = 130406690050560.

The previous prime is 131112114139991. The next prime is 131112114140009. The reversal of 131112114140003 is 300041411211131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 131112114140003 - 2¹⁰ = 131112114138979 is a prime.

It is a super-2 number, since 2×131112114140003² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131112114140009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 101089598 + ... + 102378371.

It is an arithmetic number, because the mean of its divisors is an integer number (16477243146540).

Almost surely, 2^{131112114140003} is an apocalyptic number.

131112114140003 is a deficient number, since it is larger than the sum of its proper divisors (705831032317).

131112114140003 is a wasteful number, since it uses less digits than its factorization.

131112114140003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 203471437.

The product of its (nonzero) digits is 288, while the sum is 23.

Adding to 131112114140003 its reverse (300041411211131), we get a palindrome (431153525351134).

The spelling of 131112114140003 in words is "one hundred thirty-one trillion, one hundred twelve billion, one hundred fourteen million, one hundred forty thousand, three".