Base | Representation |
---|---|
bin | 111101000011011100… |
… | …1000110000111111001 |
3 | 110112102102121110110010 |
4 | 1322012321012013321 |
5 | 4122004201224423 |
6 | 140122044012133 |
7 | 12321036512643 |
oct | 1720671060771 |
9 | 415372543403 |
10 | 131112133113 |
11 | 50671421205 |
12 | 214b1231049 |
13 | c496412c70 |
14 | 64bb085893 |
15 | 36257e4693 |
hex | 1e86e461f9 |
131112133113 has 16 divisors (see below), whose sum is σ = 188272679616. Its totient is φ = 80680488000.
The previous prime is 131112133099. The next prime is 131112133129. The reversal of 131112133113 is 311331211131.
It is not a de Polignac number, because 131112133113 - 26 = 131112133049 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131112133113.
It is not an unprimeable number, because it can be changed into a prime (131112133133) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 879238 + ... + 1017488.
It is an arithmetic number, because the mean of its divisors is an integer number (11767042476).
Almost surely, 2131112133113 is an apocalyptic number.
131112133113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
131112133113 is a deficient number, since it is larger than the sum of its proper divisors (57160546503).
131112133113 is a wasteful number, since it uses less digits than its factorization.
131112133113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 162584.
The product of its digits is 162, while the sum is 21.
Adding to 131112133113 its reverse (311331211131), we get a palindrome (442443344244).
The spelling of 131112133113 in words is "one hundred thirty-one billion, one hundred twelve million, one hundred thirty-three thousand, one hundred thirteen".
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