13111220110033 has 4 divisors (see below), whose sum is σ = 13563331148340. Its totient is φ = 12659109071728.

The previous prime is 13111220109973. The next prime is 13111220110123. The reversal of 13111220110033 is 33001102211131.

13111220110033 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 8020858380544 + 5090361729489 = 2832112^2 + 2256183^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13111220110033 is a prime.

It is a super-2 number, since 2×13111220110033² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13111220110333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 226055519110 + ... + 226055519167.

It is an arithmetic number, because the mean of its divisors is an integer number (3390832787085).

Almost surely, 2^{13111220110033} is an apocalyptic number.

It is an amenable number.

13111220110033 is a deficient number, since it is larger than the sum of its proper divisors (452111038307).

13111220110033 is an equidigital number, since it uses as much as digits as its factorization.

13111220110033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 452111038306.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 13111220110033 its reverse (33001102211131), we get a palindrome (46112322321164).

The spelling of 13111220110033 in words is "thirteen trillion, one hundred eleven billion, two hundred twenty million, one hundred ten thousand, thirty-three".