131112202211131 has 4 divisors (see below), whose sum is σ = 131173728352264. Its totient is φ = 131050676070000.

The previous prime is 131112202211077. The next prime is 131112202211147.

131112202211131 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131112202211131 is a prime.

It is a super-2 number, since 2×131112202211131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131112202211231) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30763067370 + ... + 30763071631.

It is an arithmetic number, because the mean of its divisors is an integer number (32793432088066).

Almost surely, 2^{131112202211131} is an apocalyptic number.

131112202211131 is a deficient number, since it is larger than the sum of its proper divisors (61526141133).

131112202211131 is an equidigital number, since it uses as much as digits as its factorization.

131112202211131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 61526141132.

The product of its (nonzero) digits is 144, while the sum is 22.

It can be divided in two parts, 13111220 and 2211131, that added together give a palindrome (15322351).

The spelling of 131112202211131 in words is "one hundred thirty-one trillion, one hundred twelve billion, two hundred two million, two hundred eleven thousand, one hundred thirty-one".