Base | Representation |
---|---|
bin | 1011111011001011011001… |
… | …1100111000110100000011 |
3 | 1201102102120010100222221001 |
4 | 2332302312130320310003 |
5 | 3204303421102312233 |
6 | 43515125411512431 |
7 | 2522155160325136 |
oct | 276626634706403 |
9 | 51372503328831 |
10 | 13111301213443 |
11 | 41a55207a6814 |
12 | 15790842b8717 |
13 | 74150c9266b4 |
14 | 334839d6421d |
15 | 17b0c5b0e27d |
hex | becb6738d03 |
13111301213443 has 8 divisors (see below), whose sum is σ = 13174969577616. Its totient is φ = 13047785349600.
The previous prime is 13111301213389. The next prime is 13111301213447. The reversal of 13111301213443 is 34431210311131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13111301213443 - 213 = 13111301205251 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13111301213447) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 37952713 + ... + 38296618.
It is an arithmetic number, because the mean of its divisors is an integer number (1646871197202).
Almost surely, 213111301213443 is an apocalyptic number.
13111301213443 is a deficient number, since it is larger than the sum of its proper divisors (63668364173).
13111301213443 is an equidigital number, since it uses as much as digits as its factorization.
13111301213443 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 76250165.
The product of its (nonzero) digits is 2592, while the sum is 28.
Adding to 13111301213443 its reverse (34431210311131), we get a palindrome (47542511524574).
The spelling of 13111301213443 in words is "thirteen trillion, one hundred eleven billion, three hundred one million, two hundred thirteen thousand, four hundred forty-three".
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