13111310011 has 4 divisors (see below), whose sum is σ = 13681366992. Its totient is φ = 12541253032.

The previous prime is 13111309979. The next prime is 13111310029. The reversal of 13111310011 is 11001311131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11001311131 = 12923 ⋅851297.

It is a cyclic number.

It is not a de Polignac number, because 13111310011 - 2⁵ = 13111309979 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13111309973 and 13111310000.

It is not an unprimeable number, because it can be changed into a prime (13111310081) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 285028456 + ... + 285028501.

It is an arithmetic number, because the mean of its divisors is an integer number (3420341748).

Almost surely, 2^13111310011 is an apocalyptic number.

13111310011 is a deficient number, since it is larger than the sum of its proper divisors (570056981).

13111310011 is an equidigital number, since it uses as much as digits as its factorization.

13111310011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 570056980.

The product of its (nonzero) digits is 9, while the sum is 13.

Adding to 13111310011 its reverse (11001311131), we get a palindrome (24112621142).

The spelling of 13111310011 in words is "thirteen billion, one hundred eleven million, three hundred ten thousand, eleven".