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131113113 = 3251174121
BaseRepresentation
bin1111101000010…
…10000010011001
3100010201020101020
413310022002121
5232031104423
621002113053
73151304655
oct764120231
9303636336
10131113113
116801224a
1237aab789
1321218331
14135ada65
15b79d4e3
hex7d0a099

131113113 has 8 divisors (see below), whose sum is σ = 175514976. Its totient is φ = 87060000.

The previous prime is 131113111. The next prime is 131113123. The reversal of 131113113 is 311311131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 131113113 - 21 = 131113111 is a prime.

It is a nude number because it is divisible by every one of its digits.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 131113092 and 131113101.

It is not an unprimeable number, because it can be changed into a prime (131113111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 86308 + ... + 87813.

It is an arithmetic number, because the mean of its divisors is an integer number (21939372).

Almost surely, 2131113113 is an apocalyptic number.

It is an amenable number.

131113113 is a deficient number, since it is larger than the sum of its proper divisors (44401863).

131113113 is a wasteful number, since it uses less digits than its factorization.

131113113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 174375.

The product of its digits is 27, while the sum is 15.

The square root of 131113113 is about 11450.4634404028. The cubic root of 131113113 is about 508.0214420962.

Adding to 131113113 its reverse (311311131), we get a palindrome (442424244).

The spelling of 131113113 in words is "one hundred thirty-one million, one hundred thirteen thousand, one hundred thirteen".

Divisors: 1 3 251 753 174121 522363 43704371 131113113