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131113300243 = 671956914929
BaseRepresentation
bin111101000011011110…
…1100011000100010011
3110112102111210202110011
41322012331203010103
54122010001101433
6140122125015351
712321052443442
oct1720675430423
9415374722404
10131113300243
1150672049082
12214b16b4557
13c496731283
1464bb2aad59
1536259753cd
hex1e86f63113

131113300243 has 4 divisors (see below), whose sum is σ = 133070215240. Its totient is φ = 129156385248.

The previous prime is 131113300217. The next prime is 131113300259. The reversal of 131113300243 is 342003311131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131113300243 is a prime.

It is a super-2 number, since 2×1311133002432 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131117300243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 978457398 + ... + 978457531.

It is an arithmetic number, because the mean of its divisors is an integer number (33267553810).

Almost surely, 2131113300243 is an apocalyptic number.

131113300243 is a deficient number, since it is larger than the sum of its proper divisors (1956914997).

131113300243 is an equidigital number, since it uses as much as digits as its factorization.

131113300243 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1956914996.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 131113300243 its reverse (342003311131), we get a palindrome (473116611374).

The spelling of 131113300243 in words is "one hundred thirty-one billion, one hundred thirteen million, three hundred thousand, two hundred forty-three".

Divisors: 1 67 1956914929 131113300243