13111331011033 has 4 divisors (see below), whose sum is σ = 13111631435700. Its totient is φ = 13111030586368.

The previous prime is 13111331011013. The next prime is 13111331011039. The reversal of 13111331011033 is 33011013311131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 9172884370329 + 3938446640704 = 3028677^2 + 1984552^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13111331011033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13111331010995 and 13111331011013.

It is not an unprimeable number, because it can be changed into a prime (13111331011039) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 150146860 + ... + 150234157.

It is an arithmetic number, because the mean of its divisors is an integer number (3277907858925).

Almost surely, 2^{13111331011033} is an apocalyptic number.

It is an amenable number.

13111331011033 is a deficient number, since it is larger than the sum of its proper divisors (300424667).

13111331011033 is an equidigital number, since it uses as much as digits as its factorization.

13111331011033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 300424666.

The product of its (nonzero) digits is 243, while the sum is 22.

Adding to 13111331011033 its reverse (33011013311131), we get a palindrome (46122344322164).

The spelling of 13111331011033 in words is "thirteen trillion, one hundred eleven billion, three hundred thirty-one million, eleven thousand, thirty-three".