13111331153131 has 4 divisors (see below), whose sum is σ = 13111340269392. Its totient is φ = 13111322036872.

The previous prime is 13111331153071. The next prime is 13111331153147. The reversal of 13111331153131 is 13135113311131.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 13111331153131 - 2¹⁷ = 13111331022059 is a prime.

It is a super-2 number, since 2×13111331153131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13111331153131.

It is not an unprimeable number, because it can be changed into a prime (13111331159131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1873855 + ... + 5452888.

It is an arithmetic number, because the mean of its divisors is an integer number (3277835067348).

Almost surely, 2^{13111331153131} is an apocalyptic number.

13111331153131 is a deficient number, since it is larger than the sum of its proper divisors (9116261).

13111331153131 is an equidigital number, since it uses as much as digits as its factorization.

13111331153131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9116260.

The product of its digits is 1215, while the sum is 28.

Adding to 13111331153131 its reverse (13135113311131), we get a palindrome (26246444464262).

The spelling of 13111331153131 in words is "thirteen trillion, one hundred eleven billion, three hundred thirty-one million, one hundred fifty-three thousand, one hundred thirty-one".