1311134403011 has 4 divisors (see below), whose sum is σ = 1314176478624. Its totient is φ = 1308092327400.

The previous prime is 1311134403001. The next prime is 1311134403041. The reversal of 1311134403011 is 1103044311131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1311134403011 is a prime.

It is a super-2 number, since 2×1311134403011² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1311134403001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1521037160 + ... + 1521038021.

It is an arithmetic number, because the mean of its divisors is an integer number (328544119656).

Almost surely, 2^{1311134403011} is an apocalyptic number.

1311134403011 is a deficient number, since it is larger than the sum of its proper divisors (3042075613).

1311134403011 is an equidigital number, since it uses as much as digits as its factorization.

1311134403011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3042075612.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 1311134403011 its reverse (1103044311131), we get a palindrome (2414178714142).

The spelling of 1311134403011 in words is "one trillion, three hundred eleven billion, one hundred thirty-four million, four hundred three thousand, eleven".