13111412033 has 4 divisors (see below), whose sum is σ = 13127619780. Its totient is φ = 13095204288.

The previous prime is 13111412021. The next prime is 13111412047. The reversal of 13111412033 is 33021411131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 33021411131 = 27541 ⋅1198991.

It can be written as a sum of positive squares in 2 ways, for example, as 10703350849 + 2408061184 = 103457^2 + 49072^2 .

It is a cyclic number.

It is not a de Polignac number, because 13111412033 - 2¹⁶ = 13111346497 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13111411996 and 13111412014.

It is not an unprimeable number, because it can be changed into a prime (13111412063) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8102660 + ... + 8104277.

It is an arithmetic number, because the mean of its divisors is an integer number (3281904945).

Almost surely, 2^13111412033 is an apocalyptic number.

It is an amenable number.

13111412033 is a deficient number, since it is larger than the sum of its proper divisors (16207747).

13111412033 is an equidigital number, since it uses as much as digits as its factorization.

13111412033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16207746.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 13111412033 its reverse (33021411131), we get a palindrome (46132823164).

The spelling of 13111412033 in words is "thirteen billion, one hundred eleven million, four hundred twelve thousand, thirty-three".