Base | Representation |
---|---|
bin | 10011000101000110001… |
… | …110011101101110111001 |
3 | 11122100021211021210101112 |
4 | 103011012032131232321 |
5 | 132440210131102301 |
6 | 2442155245330105 |
7 | 163504231334561 |
oct | 23050616355671 |
9 | 4570254253345 |
10 | 1311143222201 |
11 | 466064192a3a |
12 | 192137266935 |
13 | 968428b9947 |
14 | 4766149bda1 |
15 | 2418c3559bb |
hex | 1314639dbb9 |
1311143222201 has 4 divisors (see below), whose sum is σ = 1315104380304. Its totient is φ = 1307182064100.
The previous prime is 1311143222167. The next prime is 1311143222227. The reversal of 1311143222201 is 1022223411131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1311143222201 - 222 = 1311139027897 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1311143225201) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1980578555 + ... + 1980579216.
It is an arithmetic number, because the mean of its divisors is an integer number (328776095076).
Almost surely, 21311143222201 is an apocalyptic number.
It is an amenable number.
1311143222201 is a deficient number, since it is larger than the sum of its proper divisors (3961158103).
1311143222201 is an equidigital number, since it uses as much as digits as its factorization.
1311143222201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3961158102.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 1311143222201 its reverse (1022223411131), we get a palindrome (2333366633332).
The spelling of 1311143222201 in words is "one trillion, three hundred eleven billion, one hundred forty-three million, two hundred twenty-two thousand, two hundred one".
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