13111514522041 has 8 divisors (see below), whose sum is σ = 14120137393544. Its totient is φ = 12102898055040.

The previous prime is 13111514522027. The next prime is 13111514522047. The reversal of 13111514522041 is 14022541511131.

It can be written as a sum of positive squares in 4 ways, for example, as 25603600 + 13111488918441 = 5060^2 + 3620979^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13111514522041 - 2²¹ = 13111512424889 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13111514521994 and 13111514522012.

It is not an unprimeable number, because it can be changed into a prime (13111514522047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3179515 + ... + 6027631.

It is an arithmetic number, because the mean of its divisors is an integer number (1765017174193).

Almost surely, 2^{13111514522041} is an apocalyptic number.

It is an amenable number.

13111514522041 is a deficient number, since it is larger than the sum of its proper divisors (1008622871503).

13111514522041 is a wasteful number, since it uses less digits than its factorization.

13111514522041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3202251.

The product of its (nonzero) digits is 4800, while the sum is 31.

The spelling of 13111514522041 in words is "thirteen trillion, one hundred eleven billion, five hundred fourteen million, five hundred twenty-two thousand, forty-one".