13111520055313 has 4 divisors (see below), whose sum is σ = 13120433394688. Its totient is φ = 13102606715940.

The previous prime is 13111520055301. The next prime is 13111520055329. The reversal of 13111520055313 is 31355002511131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13111520055313 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13111520055343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4456667481 + ... + 4456670422.

It is an arithmetic number, because the mean of its divisors is an integer number (3280108348672).

Almost surely, 2^{13111520055313} is an apocalyptic number.

It is an amenable number.

13111520055313 is a deficient number, since it is larger than the sum of its proper divisors (8913339375).

13111520055313 is an equidigital number, since it uses as much as digits as its factorization.

13111520055313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8913339374.

The product of its (nonzero) digits is 6750, while the sum is 31.

Adding to 13111520055313 its reverse (31355002511131), we get a palindrome (44466522566444).

The spelling of 13111520055313 in words is "thirteen trillion, one hundred eleven billion, five hundred twenty million, fifty-five thousand, three hundred thirteen".