Base | Representation |
---|---|
bin | 11101110011111110100101… |
… | …010111011111110000110001 |
3 | 122012020111100120210100211020 |
4 | 131303332211113133300301 |
5 | 114141143003201420131 |
6 | 1142505302112010053 |
7 | 36421522621162611 |
oct | 3563764527376061 |
9 | 565214316710736 |
10 | 131115241045041 |
11 | 38860730447a10 |
12 | 12857018b30929 |
13 | 5821163b04bb6 |
14 | 24540238b4a41 |
15 | 102591d0c4996 |
hex | 773fa55dfc31 |
131115241045041 has 8 divisors (see below), whose sum is σ = 190713077883744. Its totient is φ = 79463782451520.
The previous prime is 131115241045003. The next prime is 131115241045051. The reversal of 131115241045041 is 140540142511131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 131115241045041 - 211 = 131115241042993 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (33), and also a Moran number because the ratio is a prime number: 3973189122577 = 131115241045041 / (1 + 3 + 1 + 1 + 1 + 5 + 2 + 4 + 1 + 0 + 4 + 5 + 0 + 4 + 1).
It is a junction number, because it is equal to n+sod(n) for n = 131115241044993 and 131115241045011.
It is not an unprimeable number, because it can be changed into a prime (131115241045051) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1986594561256 + ... + 1986594561321.
It is an arithmetic number, because the mean of its divisors is an integer number (23839134735468).
Almost surely, 2131115241045041 is an apocalyptic number.
131115241045041 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
131115241045041 is a deficient number, since it is larger than the sum of its proper divisors (59597836838703).
131115241045041 is a wasteful number, since it uses less digits than its factorization.
131115241045041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3973189122591.
The product of its (nonzero) digits is 9600, while the sum is 33.
Adding to 131115241045041 its reverse (140540142511131), we get a palindrome (271655383556172).
The spelling of 131115241045041 in words is "one hundred thirty-one trillion, one hundred fifteen billion, two hundred forty-one million, forty-five thousand, forty-one".
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