1311200031113 has 4 divisors (see below), whose sum is σ = 1498514321280. Its totient is φ = 1123885740948.

The previous prime is 1311200031073. The next prime is 1311200031121. The reversal of 1311200031113 is 3111300021131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1311200031113 - 2⁸ = 1311200030857 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1311200031091 and 1311200031100.

It is not an unprimeable number, because it can be changed into a prime (1311200051113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 93657145073 + ... + 93657145086.

It is an arithmetic number, because the mean of its divisors is an integer number (374628580320).

Almost surely, 2^{1311200031113} is an apocalyptic number.

It is an amenable number.

1311200031113 is a deficient number, since it is larger than the sum of its proper divisors (187314290167).

1311200031113 is an equidigital number, since it uses as much as digits as its factorization.

1311200031113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 187314290166.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1311200031113 its reverse (3111300021131), we get a palindrome (4422500052244).

The spelling of 1311200031113 in words is "one trillion, three hundred eleven billion, two hundred million, thirty-one thousand, one hundred thirteen".