Base | Representation |
---|---|
bin | 1011111011001110000101… |
… | …0100011000000011100011 |
3 | 1201102111102020122120201012 |
4 | 2332303201110120003203 |
5 | 3204311404210334103 |
6 | 43515325022331135 |
7 | 2522212042330016 |
oct | 276634124300343 |
9 | 51374366576635 |
10 | 13112020402403 |
11 | 41a585a76205a |
12 | 1579245129aab |
13 | 7415c5923cb0 |
14 | 3348a769537d |
15 | 17b118d222d8 |
hex | bece15180e3 |
13112020402403 has 8 divisors (see below), whose sum is σ = 14136205877808. Its totient is φ = 12090059001504.
The previous prime is 13112020402319. The next prime is 13112020402423. The reversal of 13112020402403 is 30420402021131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13112020402403 - 218 = 13112020140259 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13112020402423) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 556006376 + ... + 556029957.
It is an arithmetic number, because the mean of its divisors is an integer number (1767025734726).
Almost surely, 213112020402403 is an apocalyptic number.
13112020402403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
13112020402403 is a deficient number, since it is larger than the sum of its proper divisors (1024185475405).
13112020402403 is a wasteful number, since it uses less digits than its factorization.
13112020402403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1112037253.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 13112020402403 its reverse (30420402021131), we get a palindrome (43532422423534).
The spelling of 13112020402403 in words is "thirteen trillion, one hundred twelve billion, twenty million, four hundred two thousand, four hundred three".
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