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131120220323 = 157835160639
BaseRepresentation
bin111101000011101011…
…1111100100010100011
3110112102222211100000102
41322013113330202203
54122013234022243
6140122533213015
712321165324551
oct1720727744243
9415388740012
10131120220323
1150675a45254
12214b3a9116b
13c497cb4cb1
1464bc18cbd1
1536263909b8
hex1e875fc8a3

131120220323 has 4 divisors (see below), whose sum is σ = 131955381120. Its totient is φ = 130285059528.

The previous prime is 131120220299. The next prime is 131120220331. The reversal of 131120220323 is 323022021131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131120220323 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131120220295 and 131120220304.

It is not an unprimeable number, because it can be changed into a prime (131120220223) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 417580163 + ... + 417580476.

It is an arithmetic number, because the mean of its divisors is an integer number (32988845280).

Almost surely, 2131120220323 is an apocalyptic number.

131120220323 is a deficient number, since it is larger than the sum of its proper divisors (835160797).

131120220323 is an equidigital number, since it uses as much as digits as its factorization.

131120220323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 835160796.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 131120220323 its reverse (323022021131), we get a palindrome (454142241454).

The spelling of 131120220323 in words is "one hundred thirty-one billion, one hundred twenty million, two hundred twenty thousand, three hundred twenty-three".

Divisors: 1 157 835160639 131120220323