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13112022203003 = 19690106431737
BaseRepresentation
bin1011111011001110000101…
…1011001111101001111011
31201102111102101001001200002
42332303201123033221323
53204311410140444003
643515325125103215
72522212063536413
oct276634133175173
951374371031602
1013112022203003
1141a5860781959
121579245857b0b
137415c6104739
143348a7a03643
1517b11907aa88
hexbece16cfa7b

13112022203003 has 4 divisors (see below), whose sum is σ = 13802128634760. Its totient is φ = 12421915771248.

The previous prime is 13112022202943. The next prime is 13112022203069. The reversal of 13112022203003 is 30030222021131.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 13112022203003 - 214 = 13112022186619 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13112022203503) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 345053215850 + ... + 345053215887.

It is an arithmetic number, because the mean of its divisors is an integer number (3450532158690).

Almost surely, 213112022203003 is an apocalyptic number.

13112022203003 is a deficient number, since it is larger than the sum of its proper divisors (690106431757).

13112022203003 is an equidigital number, since it uses as much as digits as its factorization.

13112022203003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 690106431756.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 13112022203003 its reverse (30030222021131), we get a palindrome (43142244224134).

The spelling of 13112022203003 in words is "thirteen trillion, one hundred twelve billion, twenty-two million, two hundred three thousand, three".

Divisors: 1 19 690106431737 13112022203003