13112101113 has 8 divisors (see below), whose sum is σ = 17498656128. Its totient is φ = 8733473424.

The previous prime is 13112101111. The next prime is 13112101129. The reversal of 13112101113 is 31110121131.

13112101113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13112101113 - 2¹ = 13112101111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13112101092 and 13112101101.

It is not an unprimeable number, because it can be changed into a prime (13112101111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1977970 + ... + 1984587.

It is an arithmetic number, because the mean of its divisors is an integer number (2187332016).

Almost surely, 2^13112101113 is an apocalyptic number.

It is an amenable number.

13112101113 is a deficient number, since it is larger than the sum of its proper divisors (4386555015).

13112101113 is a wasteful number, since it uses less digits than its factorization.

13112101113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3963663.

The product of its (nonzero) digits is 18, while the sum is 15.

Adding to 13112101113 its reverse (31110121131), we get a palindrome (44222222244).

The spelling of 13112101113 in words is "thirteen billion, one hundred twelve million, one hundred one thousand, one hundred thirteen".