13112101321113 has 4 divisors (see below), whose sum is σ = 17482801761488. Its totient is φ = 8741400880740.

The previous prime is 13112101321073. The next prime is 13112101321127. The reversal of 13112101321113 is 31112310121131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13112101321113 - 2³⁴ = 13094921451929 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13112101321113.

It is not an unprimeable number, because it can be changed into a prime (13112101321153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2185350220183 + ... + 2185350220188.

It is an arithmetic number, because the mean of its divisors is an integer number (4370700440372).

Almost surely, 2^{13112101321113} is an apocalyptic number.

It is an amenable number.

13112101321113 is a deficient number, since it is larger than the sum of its proper divisors (4370700440375).

13112101321113 is an equidigital number, since it uses as much as digits as its factorization.

13112101321113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4370700440374.

The product of its (nonzero) digits is 108, while the sum is 21.

Adding to 13112101321113 its reverse (31112310121131), we get a palindrome (44224411442244).

The spelling of 13112101321113 in words is "thirteen trillion, one hundred twelve billion, one hundred one million, three hundred twenty-one thousand, one hundred thirteen".