Base | Representation |
---|---|
bin | 111101000011101101… |
… | …1000010100010100011 |
3 | 110112110001100112111202 |
4 | 1322013123002202203 |
5 | 4122013441000311 |
6 | 140123002431415 |
7 | 12321205243163 |
oct | 1720733024243 |
9 | 415401315452 |
10 | 131121031331 |
11 | 50676449604 |
12 | 214b420256b |
13 | c49820a194 |
14 | 64bc3205a3 |
15 | 36264a0e3b |
hex | 1e876c28a3 |
131121031331 has 4 divisors (see below), whose sum is σ = 138834033192. Its totient is φ = 123408029472.
The previous prime is 131121031291. The next prime is 131121031339. The reversal of 131121031331 is 133130121131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131121031331 - 234 = 113941162147 is a prime.
It is a super-2 number, since 2×1311210313312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131121031339) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3856500905 + ... + 3856500938.
It is an arithmetic number, because the mean of its divisors is an integer number (34708508298).
Almost surely, 2131121031331 is an apocalyptic number.
131121031331 is a deficient number, since it is larger than the sum of its proper divisors (7713001861).
131121031331 is an equidigital number, since it uses as much as digits as its factorization.
131121031331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7713001860.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 131121031331 its reverse (133130121131), we get a palindrome (264251152462).
The spelling of 131121031331 in words is "one hundred thirty-one billion, one hundred twenty-one million, thirty-one thousand, three hundred thirty-one".
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