1311211110201 has 4 divisors (see below), whose sum is σ = 1748281480272. Its totient is φ = 874140740132.

The previous prime is 1311211110179. The next prime is 1311211110221. The reversal of 1311211110201 is 1020111121131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1311211110201 - 2¹³ = 1311211102009 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1311211110221) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218535185031 + ... + 218535185036.

It is an arithmetic number, because the mean of its divisors is an integer number (437070370068).

Almost surely, 2^{1311211110201} is an apocalyptic number.

It is an amenable number.

1311211110201 is a deficient number, since it is larger than the sum of its proper divisors (437070370071).

1311211110201 is an equidigital number, since it uses as much as digits as its factorization.

1311211110201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 437070370070.

The product of its (nonzero) digits is 12, while the sum is 15.

Adding to 1311211110201 its reverse (1020111121131), we get a palindrome (2331322231332).

The spelling of 1311211110201 in words is "one trillion, three hundred eleven billion, two hundred eleven million, one hundred ten thousand, two hundred one".