Base | Representation |
---|---|
bin | 1011111011001110011101… |
… | …0101011000111000001011 |
3 | 1201102111200021120022000012 |
4 | 2332303213111120320023 |
5 | 3204312111030044321 |
6 | 43515343025502135 |
7 | 2522214406241060 |
oct | 276634725307013 |
9 | 51374607508005 |
10 | 13112121331211 |
11 | 41a59017283a1 |
12 | 1579272aa194b |
13 | 741610801496 |
14 | 3348b6c48c67 |
15 | 17b122b0c05b |
hex | bece7558e0b |
13112121331211 has 4 divisors (see below), whose sum is σ = 14985281521392. Its totient is φ = 11238961141032.
The previous prime is 13112121331181. The next prime is 13112121331261. The reversal of 13112121331211 is 11213312121131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13112121331211 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13112121331261) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 936580095080 + ... + 936580095093.
It is an arithmetic number, because the mean of its divisors is an integer number (3746320380348).
Almost surely, 213112121331211 is an apocalyptic number.
13112121331211 is a deficient number, since it is larger than the sum of its proper divisors (1873160190181).
13112121331211 is an equidigital number, since it uses as much as digits as its factorization.
13112121331211 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1873160190180.
The product of its digits is 216, while the sum is 23.
Adding to 13112121331211 its reverse (11213312121131), we get a palindrome (24325433452342).
The spelling of 13112121331211 in words is "thirteen trillion, one hundred twelve billion, one hundred twenty-one million, three hundred thirty-one thousand, two hundred eleven".
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