13112123301131 has 4 divisors (see below), whose sum is σ = 13114375862064. Its totient is φ = 13109870740200.

The previous prime is 13112123301127. The next prime is 13112123301187. The reversal of 13112123301131 is 13110332121131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13112123301131 - 2² = 13112123301127 is a prime.

It is a super-2 number, since 2×13112123301131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13112123301097 and 13112123301106.

It is not an unprimeable number, because it can be changed into a prime (13112123301731) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1126271735 + ... + 1126283376.

It is an arithmetic number, because the mean of its divisors is an integer number (3278593965516).

Almost surely, 2^{13112123301131} is an apocalyptic number.

13112123301131 is a deficient number, since it is larger than the sum of its proper divisors (2252560933).

13112123301131 is an equidigital number, since it uses as much as digits as its factorization.

13112123301131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2252560932.

The product of its (nonzero) digits is 324, while the sum is 23.

Adding to 13112123301131 its reverse (13110332121131), we get a palindrome (26222455422262).

The spelling of 13112123301131 in words is "thirteen trillion, one hundred twelve billion, one hundred twenty-three million, three hundred one thousand, one hundred thirty-one".