13112130000113 has 4 divisors (see below), whose sum is σ = 13564272413940. Its totient is φ = 12659987586288.

The previous prime is 13112130000043. The next prime is 13112130000139. The reversal of 13112130000113 is 31100003121131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 10105710386704 + 3006419613409 = 3178948^2 + 1733903^2 .

It is a cyclic number.

It is not a de Polignac number, because 13112130000113 - 2¹⁶ = 13112129934577 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13112130000091 and 13112130000100.

It is not an unprimeable number, because it can be changed into a prime (13112130000173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 226071206870 + ... + 226071206927.

It is an arithmetic number, because the mean of its divisors is an integer number (3391068103485).

Almost surely, 2^{13112130000113} is an apocalyptic number.

It is an amenable number.

13112130000113 is a deficient number, since it is larger than the sum of its proper divisors (452142413827).

13112130000113 is an equidigital number, since it uses as much as digits as its factorization.

13112130000113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 452142413826.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 13112130000113 its reverse (31100003121131), we get a palindrome (44212133121244).

The spelling of 13112130000113 in words is "thirteen trillion, one hundred twelve billion, one hundred thirty million, one hundred thirteen", and thus it is an aban number.