131121304512531 has 4 divisors (see below), whose sum is σ = 174828406016712. Its totient is φ = 87414203008352.

The previous prime is 131121304512481. The next prime is 131121304512533. The reversal of 131121304512531 is 135215403121131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131121304512531 - 2²² = 131121300318227 is a prime.

It is a super-2 number, since 2×131121304512531² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131121304512492 and 131121304512501.

It is not an unprimeable number, because it can be changed into a prime (131121304512533) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21853550752086 + ... + 21853550752091.

It is an arithmetic number, because the mean of its divisors is an integer number (43707101504178).

Almost surely, 2^{131121304512531} is an apocalyptic number.

131121304512531 is a deficient number, since it is larger than the sum of its proper divisors (43707101504181).

131121304512531 is an equidigital number, since it uses as much as digits as its factorization.

131121304512531 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43707101504180.

The product of its (nonzero) digits is 10800, while the sum is 33.

Adding to 131121304512531 its reverse (135215403121131), we get a palindrome (266336707633662).

The spelling of 131121304512531 in words is "one hundred thirty-one trillion, one hundred twenty-one billion, three hundred four million, five hundred twelve thousand, five hundred thirty-one".