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131121351023251 = 197966256367369
BaseRepresentation
bin11101110100000100010001…
…100011001101101010010011
3122012021002010101210102020111
4131310010101203031222103
5114141243011330221001
61142512152254022151
736422130212142301
oct3564042143155223
9565232111712214
10131121351023251
1138863286364a86
12128582431a7957
1358218c88c9114
142454443151271
151025b796d3851
hex7741118cda93

131121351023251 has 4 divisors (see below), whose sum is σ = 131187607392600. Its totient is φ = 131055094653904.

The previous prime is 131121351023249. The next prime is 131121351023279. The reversal of 131121351023251 is 152320153121131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131121351023251 - 21 = 131121351023249 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131121351023651) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33128181706 + ... + 33128185663.

It is an arithmetic number, because the mean of its divisors is an integer number (32796901848150).

Almost surely, 2131121351023251 is an apocalyptic number.

131121351023251 is a deficient number, since it is larger than the sum of its proper divisors (66256369349).

131121351023251 is an equidigital number, since it uses as much as digits as its factorization.

131121351023251 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66256369348.

The product of its (nonzero) digits is 5400, while the sum is 31.

The spelling of 131121351023251 in words is "one hundred thirty-one trillion, one hundred twenty-one billion, three hundred fifty-one million, twenty-three thousand, two hundred fifty-one".

Divisors: 1 1979 66256367369 131121351023251