1311214433 has 4 divisors (see below), whose sum is σ = 1311288468. Its totient is φ = 1311140400.

The previous prime is 1311214417. The next prime is 1311214441. The reversal of 1311214433 is 3344121131.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 375894544 + 935319889 = 19388^2 + 30583^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311214433 - 2⁴ = 1311214417 is a prime.

It is a super-2 number, since 2×1311214433² = 3438566578615022978, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1311214399 and 1311214408.

It is not an unprimeable number, because it can be changed into a prime (1311214133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6983 + ... + 51683.

It is an arithmetic number, because the mean of its divisors is an integer number (327822117).

Almost surely, 2^1311214433 is an apocalyptic number.

It is an amenable number.

1311214433 is a deficient number, since it is larger than the sum of its proper divisors (74035).

1311214433 is an equidigital number, since it uses as much as digits as its factorization.

1311214433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 74034.

The product of its digits is 864, while the sum is 23.

The square root of 1311214433 is about 36210.6950085192. The cubic root of 1311214433 is about 1094.5221973851.

Adding to 1311214433 its reverse (3344121131), we get a palindrome (4655335564).

The spelling of 1311214433 in words is "one billion, three hundred eleven million, two hundred fourteen thousand, four hundred thirty-three".