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13112201110331 = 60792156966789
BaseRepresentation
bin1011111011001110110000…
…0101101110001100111011
31201102111212211200111101102
42332303230011232030323
53204312241441012311
643515354555442015
72522216365324211
oct276635405561473
951374784614342
1013112201110331
1141a5942768654
12157929575630b
137416241b516b
143348c3694cb1
1517b129b1a43b
hexbecec16e33b

13112201110331 has 4 divisors (see below), whose sum is σ = 13114358083200. Its totient is φ = 13110044137464.

The previous prime is 13112201110277. The next prime is 13112201110361. The reversal of 13112201110331 is 13301110221131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13112201110331 is a prime.

It is a super-2 number, since 2×131122011103312 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13112201110361) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1078477316 + ... + 1078489473.

It is an arithmetic number, because the mean of its divisors is an integer number (3278589520800).

Almost surely, 213112201110331 is an apocalyptic number.

13112201110331 is a deficient number, since it is larger than the sum of its proper divisors (2156972869).

13112201110331 is an equidigital number, since it uses as much as digits as its factorization.

13112201110331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2156972868.

The product of its (nonzero) digits is 108, while the sum is 20.

Adding to 13112201110331 its reverse (13301110221131), we get a palindrome (26413311331462).

The spelling of 13112201110331 in words is "thirteen trillion, one hundred twelve billion, two hundred one million, one hundred ten thousand, three hundred thirty-one".

Divisors: 1 6079 2156966789 13112201110331