Base | Representation |
---|---|
bin | 11101110100000101001011… |
… | …100100000011111101101001 |
3 | 122012021011122020020020010211 |
4 | 131310011023210003331221 |
5 | 114141302010011333301 |
6 | 1142512433023141121 |
7 | 36422163301103350 |
oct | 3564051344037551 |
9 | 565234566206124 |
10 | 131122324324201 |
11 | 38863735802431 |
12 | 128584751447a1 |
13 | 5821a22448942 |
14 | 24544d650c997 |
15 | 1025bd4d8e051 |
hex | 77414b903f69 |
131122324324201 has 8 divisors (see below), whose sum is σ = 149854160489024. Its totient is φ = 112390507046160.
The previous prime is 131122324324163. The next prime is 131122324324223. The reversal of 131122324324201 is 102423423221131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 131122324324201 - 29 = 131122324323689 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131122324324261) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16534831 + ... + 23144011.
It is an arithmetic number, because the mean of its divisors is an integer number (18731770061128).
Almost surely, 2131122324324201 is an apocalyptic number.
It is an amenable number.
131122324324201 is a deficient number, since it is larger than the sum of its proper divisors (18731836164823).
131122324324201 is an equidigital number, since it uses as much as digits as its factorization.
131122324324201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9443391.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 131122324324201 its reverse (102423423221131), we get a palindrome (233545747545332).
The spelling of 131122324324201 in words is "one hundred thirty-one trillion, one hundred twenty-two billion, three hundred twenty-four million, three hundred twenty-four thousand, two hundred one".
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