13112301300001 has 4 divisors (see below), whose sum is σ = 13143595575600. Its totient is φ = 13081007024404.

The previous prime is 13112301299963. The next prime is 13112301300017. The reversal of 13112301300001 is 10000310321131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13112301300001 - 2²⁵ = 13112267745569 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13112301300061) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15647137171 + ... + 15647138008.

It is an arithmetic number, because the mean of its divisors is an integer number (3285898893900).

Almost surely, 2^{13112301300001} is an apocalyptic number.

It is an amenable number.

13112301300001 is a deficient number, since it is larger than the sum of its proper divisors (31294275599).

13112301300001 is an equidigital number, since it uses as much as digits as its factorization.

13112301300001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31294275598.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 13112301300001 its reverse (10000310321131), we get a palindrome (23112611621132).

The spelling of 13112301300001 in words is "thirteen trillion, one hundred twelve billion, three hundred one million, three hundred thousand, one".