Base | Representation |
---|---|
bin | 111101000011110001… |
… | …1000000111111000001 |
3 | 110112110012021202112010 |
4 | 1322013203000333001 |
5 | 4122020004401423 |
6 | 140123115323133 |
7 | 12321232101564 |
oct | 1720743007701 |
9 | 415405252463 |
10 | 131123122113 |
11 | 50677647425 |
12 | 214b4a504a9 |
13 | c49878ca29 |
14 | 64bc7064db |
15 | 3626765693 |
hex | 1e878c0fc1 |
131123122113 has 4 divisors (see below), whose sum is σ = 174830829488. Its totient is φ = 87415414740.
The previous prime is 131123122099. The next prime is 131123122133. The reversal of 131123122113 is 311221321131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 131123122113 - 210 = 131123121089 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 131123122113.
It is not an unprimeable number, because it can be changed into a prime (131123122133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21853853683 + ... + 21853853688.
It is an arithmetic number, because the mean of its divisors is an integer number (43707707372).
Almost surely, 2131123122113 is an apocalyptic number.
It is an amenable number.
131123122113 is a deficient number, since it is larger than the sum of its proper divisors (43707707375).
131123122113 is an equidigital number, since it uses as much as digits as its factorization.
131123122113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43707707374.
The product of its digits is 216, while the sum is 21.
Adding to 131123122113 its reverse (311221321131), we get a palindrome (442344443244).
The spelling of 131123122113 in words is "one hundred thirty-one billion, one hundred twenty-three million, one hundred twenty-two thousand, one hundred thirteen".
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