13112333331113 has 4 divisors (see below), whose sum is σ = 13113775682448. Its totient is φ = 13110890979780.

The previous prime is 13112333331089. The next prime is 13112333331151. The reversal of 13112333331113 is 31113333321131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13112333331113 - 2²⁶ = 13112266222249 is a prime.

It is a super-3 number, since 3×13112333331113³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13112333331193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 721162031 + ... + 721180212.

It is an arithmetic number, because the mean of its divisors is an integer number (3278443920612).

Almost surely, 2^{13112333331113} is an apocalyptic number.

It is an amenable number.

13112333331113 is a deficient number, since it is larger than the sum of its proper divisors (1442351335).

13112333331113 is an equidigital number, since it uses as much as digits as its factorization.

13112333331113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1442351334.

The product of its digits is 4374, while the sum is 29.

Adding to 13112333331113 its reverse (31113333321131), we get a palindrome (44225666652244).

The spelling of 13112333331113 in words is "thirteen trillion, one hundred twelve billion, three hundred thirty-three million, three hundred thirty-one thousand, one hundred thirteen".