13112442455531 has 4 divisors (see below), whose sum is σ = 13883762599992. Its totient is φ = 12341122311072.

The previous prime is 13112442455507. The next prime is 13112442455533. The reversal of 13112442455531 is 13555424421131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13112442455531 is a prime.

It is a super-2 number, since 2×13112442455531² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13112442455533) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 385660072205 + ... + 385660072238.

It is an arithmetic number, because the mean of its divisors is an integer number (3470940649998).

Almost surely, 2^{13112442455531} is an apocalyptic number.

13112442455531 is a deficient number, since it is larger than the sum of its proper divisors (771320144461).

13112442455531 is an equidigital number, since it uses as much as digits as its factorization.

13112442455531 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 771320144460.

The product of its digits is 288000, while the sum is 41.

Adding to 13112442455531 its reverse (13555424421131), we get a palindrome (26667866876662).

The spelling of 13112442455531 in words is "thirteen trillion, one hundred twelve billion, four hundred forty-two million, four hundred fifty-five thousand, five hundred thirty-one".