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1311244323043 = 2357010622741
BaseRepresentation
bin10011000101001100010…
…000001000100011100011
311122100112212112020200011
4103011030100020203203
5132440412021314133
62442213300305351
7163506566563324
oct23051420104343
94570485466604
101311244323043
11466106266556
121921650a2257
139685a827525
1447670a9844b
15241961766cd
hex1314c4088e3

1311244323043 has 4 divisors (see below), whose sum is σ = 1368254945808. Its totient is φ = 1254233700280.

The previous prime is 1311244323041. The next prime is 1311244323049. The reversal of 1311244323043 is 3403234421131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1311244323043 - 21 = 1311244323041 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1311244322996 and 1311244323014.

It is not an unprimeable number, because it can be changed into a prime (1311244323041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28505311348 + ... + 28505311393.

It is an arithmetic number, because the mean of its divisors is an integer number (342063736452).

Almost surely, 21311244323043 is an apocalyptic number.

1311244323043 is a deficient number, since it is larger than the sum of its proper divisors (57010622765).

1311244323043 is an equidigital number, since it uses as much as digits as its factorization.

1311244323043 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 57010622764.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 1311244323043 its reverse (3403234421131), we get a palindrome (4714478744174).

The spelling of 1311244323043 in words is "one trillion, three hundred eleven billion, two hundred forty-four million, three hundred twenty-three thousand, forty-three".

Divisors: 1 23 57010622741 1311244323043