13112514101033 has 4 divisors (see below), whose sum is σ = 13802646422160. Its totient is φ = 12422381779908.

The previous prime is 13112514101017. The next prime is 13112514101039. The reversal of 13112514101033 is 33010141521131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13112514101033 - 2⁴ = 13112514101017 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13112514100993 and 13112514101011.

It is not an unprimeable number, because it can be changed into a prime (13112514101039) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 345066160535 + ... + 345066160572.

It is an arithmetic number, because the mean of its divisors is an integer number (3450661605540).

Almost surely, 2^{13112514101033} is an apocalyptic number.

It is an amenable number.

13112514101033 is a deficient number, since it is larger than the sum of its proper divisors (690132321127).

13112514101033 is an equidigital number, since it uses as much as digits as its factorization.

13112514101033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 690132321126.

The product of its (nonzero) digits is 1080, while the sum is 26.

Adding to 13112514101033 its reverse (33010141521131), we get a palindrome (46122655622164).

The spelling of 13112514101033 in words is "thirteen trillion, one hundred twelve billion, five hundred fourteen million, one hundred one thousand, thirty-three".