Base | Representation |
---|---|
bin | 1011111011001111111011… |
… | …0000000111100110100001 |
3 | 1201102112200122211211021220 |
4 | 2332303332300013212201 |
5 | 3204313412114324210 |
6 | 43515450022405253 |
7 | 2522230216551612 |
oct | 276637660074641 |
9 | 51375618754256 |
10 | 13112514214305 |
11 | 41a5a93482270 |
12 | 1579362590829 |
13 | 74167402059c |
14 | 3349130b9c09 |
15 | 17b147366c70 |
hex | becfec079a1 |
13112514214305 has 16 divisors (see below), whose sum is σ = 22887297537984. Its totient is φ = 6357582649280.
The previous prime is 13112514214279. The next prime is 13112514214351. The reversal of 13112514214305 is 50341241521131.
It is not a de Polignac number, because 13112514214305 - 29 = 13112514213793 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 39734891394 + ... + 39734891723.
It is an arithmetic number, because the mean of its divisors is an integer number (1430456096124).
Almost surely, 213112514214305 is an apocalyptic number.
13112514214305 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
13112514214305 is a deficient number, since it is larger than the sum of its proper divisors (9774783323679).
13112514214305 is a wasteful number, since it uses less digits than its factorization.
13112514214305 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 79469783136.
The product of its (nonzero) digits is 14400, while the sum is 33.
Adding to 13112514214305 its reverse (50341241521131), we get a palindrome (63453755735436).
The spelling of 13112514214305 in words is "thirteen trillion, one hundred twelve billion, five hundred fourteen million, two hundred fourteen thousand, three hundred five".
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