131130012431243 has 4 divisors (see below), whose sum is σ = 149862871350000. Its totient is φ = 112397153512488.

The previous prime is 131130012431213. The next prime is 131130012431251. The reversal of 131130012431243 is 342134210031131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131130012431243 - 2²² = 131130008236939 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131130012431203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9366429459368 + ... + 9366429459381.

It is an arithmetic number, because the mean of its divisors is an integer number (37465717837500).

Almost surely, 2^{131130012431243} is an apocalyptic number.

131130012431243 is a deficient number, since it is larger than the sum of its proper divisors (18732858918757).

131130012431243 is an equidigital number, since it uses as much as digits as its factorization.

131130012431243 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18732858918756.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 131130012431243 its reverse (342134210031131), we get a palindrome (473264222462374).

The spelling of 131130012431243 in words is "one hundred thirty-one trillion, one hundred thirty billion, twelve million, four hundred thirty-one thousand, two hundred forty-three".