13113011300003 has 4 divisors (see below), whose sum is σ = 13113378348840. Its totient is φ = 13112644251168.

The previous prime is 13113011299979. The next prime is 13113011300029. The reversal of 13113011300003 is 30000311031131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13113011300003 - 2⁶ = 13113011299939 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13113011300033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 183470825 + ... + 183542282.

It is an arithmetic number, because the mean of its divisors is an integer number (3278344587210).

Almost surely, 2^{13113011300003} is an apocalyptic number.

13113011300003 is a deficient number, since it is larger than the sum of its proper divisors (367048837).

13113011300003 is an equidigital number, since it uses as much as digits as its factorization.

13113011300003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 367048836.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 13113011300003 its reverse (30000311031131), we get a palindrome (43113322331134).

The spelling of 13113011300003 in words is "thirteen trillion, one hundred thirteen billion, eleven million, three hundred thousand, three".