13113042113 has 4 divisors (see below), whose sum is σ = 13113458688. Its totient is φ = 13112625540.

The previous prime is 13113042101. The next prime is 13113042119. The reversal of 13113042113 is 31124031131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31124031131 = 853 ⋅36487727.

It is a cyclic number.

It is not a de Polignac number, because 13113042113 - 2³⁰ = 12039300289 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13113042119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 156833 + ... + 225438.

It is an arithmetic number, because the mean of its divisors is an integer number (3278364672).

Almost surely, 2^13113042113 is an apocalyptic number.

It is an amenable number.

13113042113 is a deficient number, since it is larger than the sum of its proper divisors (416575).

13113042113 is an equidigital number, since it uses as much as digits as its factorization.

13113042113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 416574.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 13113042113 its reverse (31124031131), we get a palindrome (44237073244).

The spelling of 13113042113 in words is "thirteen billion, one hundred thirteen million, forty-two thousand, one hundred thirteen".