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1311312023097 = 31094010128511
BaseRepresentation
bin10011000101010000010…
…010011000111000111001
311122100201120220202200120
4103011100102120320321
5132441031334214342
62442224115323453
7163511351200506
oct23052022307071
94570646822616
101311312023097
114661404a660a
121921838b0589
139686b86c22b
1447679a7c4ad
152419c09aaec
hex13150498e39

1311312023097 has 8 divisors (see below), whose sum is σ = 1764456545280. Its totient is φ = 866187758160.

The previous prime is 1311312023051. The next prime is 1311312023113. The reversal of 1311312023097 is 7903202131131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1311312023097 - 212 = 1311312019001 is a prime.

It is a super-2 number, since 2×13113120230972 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1311312023017) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2005063929 + ... + 2005064582.

It is an arithmetic number, because the mean of its divisors is an integer number (220557068160).

Almost surely, 21311312023097 is an apocalyptic number.

It is an amenable number.

1311312023097 is a deficient number, since it is larger than the sum of its proper divisors (453144522183).

1311312023097 is a wasteful number, since it uses less digits than its factorization.

1311312023097 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4010128623.

The product of its (nonzero) digits is 6804, while the sum is 33.

The spelling of 1311312023097 in words is "one trillion, three hundred eleven billion, three hundred twelve million, twenty-three thousand, ninety-seven".

Divisors: 1 3 109 327 4010128511 12030385533 437104007699 1311312023097