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1311312121145 = 513157112841523
BaseRepresentation
bin10011000101010000010…
…010110000110100111001
311122100201121002202011222
4103011100102300310321
5132441031400334040
62442224121401425
7163511352056405
oct23052022606471
94570647082158
101311312121145
11466140563244
12192183939275
139686b8a4a50
1447679aa6105
152419c0b9bb5
hex131504b0d39

1311312121145 has 16 divisors (see below), whose sum is σ = 1695697561152. Its totient is φ = 967737097920.

The previous prime is 1311312121103. The next prime is 1311312121153. The reversal of 1311312121145 is 5411212131131.

It is not a de Polignac number, because 1311312121145 - 26 = 1311312121081 is a prime.

It is a super-2 number, since 2×13113121211452 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6318647 + ... + 6522876.

It is an arithmetic number, because the mean of its divisors is an integer number (105981097572).

Almost surely, 21311312121145 is an apocalyptic number.

It is an amenable number.

1311312121145 is a deficient number, since it is larger than the sum of its proper divisors (384385440007).

1311312121145 is a wasteful number, since it uses less digits than its factorization.

1311312121145 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12843112.

The product of its digits is 720, while the sum is 26.

Adding to 1311312121145 its reverse (5411212131131), we get a palindrome (6722524252276).

The spelling of 1311312121145 in words is "one trillion, three hundred eleven billion, three hundred twelve million, one hundred twenty-one thousand, one hundred forty-five".

Divisors: 1 5 13 65 1571 7855 20423 102115 12841523 64207615 166939799 834698995 20174032633 100870163165 262262424229 1311312121145