Base | Representation |
---|---|
bin | 11101110100001101011111… |
… | …001110110110100010110001 |
3 | 122012022000122212122001120020 |
4 | 131310031133032312202301 |
5 | 114141423242011234441 |
6 | 1142520510104034053 |
7 | 36422630322133023 |
oct | 3564153716664261 |
9 | 565260585561506 |
10 | 131131244243121 |
11 | 388674a2877551 |
12 | 1285a144462929 |
13 | 582281443a985 |
14 | 2454b0103a013 |
15 | 1026057eece66 |
hex | 77435f3b68b1 |
131131244243121 has 8 divisors (see below), whose sum is σ = 174854953976064. Its totient is φ = 87414182002800.
The previous prime is 131131244243089. The next prime is 131131244243123. The reversal of 131131244243121 is 121342442131131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 131131244243121 - 25 = 131131244243089 is a prime.
It is not an unprimeable number, because it can be changed into a prime (131131244243123) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1661827126 + ... + 1661906031.
It is an arithmetic number, because the mean of its divisors is an integer number (21856869247008).
Almost surely, 2131131244243121 is an apocalyptic number.
It is an amenable number.
131131244243121 is a deficient number, since it is larger than the sum of its proper divisors (43723709732943).
131131244243121 is a wasteful number, since it uses less digits than its factorization.
131131244243121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3323746311.
The product of its digits is 13824, while the sum is 33.
Adding to 131131244243121 its reverse (121342442131131), we get a palindrome (252473686374252).
The spelling of 131131244243121 in words is "one hundred thirty-one trillion, one hundred thirty-one billion, two hundred forty-four million, two hundred forty-three thousand, one hundred twenty-one".
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