131132001331 has 4 divisors (see below), whose sum is σ = 131889989952. Its totient is φ = 130374012712.

The previous prime is 131132001311. The next prime is 131132001367. The reversal of 131132001331 is 133100231131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131132001331 - 2¹⁵ = 131131968563 is a prime.

It is a super-2 number, since 2×131132001331² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131132001299 and 131132001308.

It is not an unprimeable number, because it can be changed into a prime (131132001311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 378994051 + ... + 378994396.

It is an arithmetic number, because the mean of its divisors is an integer number (32972497488).

Almost surely, 2^131132001331 is an apocalyptic number.

131132001331 is a deficient number, since it is larger than the sum of its proper divisors (757988621).

131132001331 is an equidigital number, since it uses as much as digits as its factorization.

131132001331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 757988620.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 131132001331 its reverse (133100231131), we get a palindrome (264232232462).

The spelling of 131132001331 in words is "one hundred thirty-one billion, one hundred thirty-two million, one thousand, three hundred thirty-one".