Base | Representation |
---|---|
bin | 111101000100000010… |
… | …1101011110010010011 |
3 | 110112110211101111012111 |
4 | 1322020011223302103 |
5 | 4122024321212243 |
6 | 140124042210151 |
7 | 12321402253042 |
oct | 1721005536223 |
9 | 415424344174 |
10 | 131132210323 |
11 | 50681794544 |
12 | 214b7ab3957 |
13 | c49a62257a |
14 | 64bd9d0559 |
15 | 362745d39d |
hex | 1e8816bc93 |
131132210323 has 4 divisors (see below), whose sum is σ = 133089407560. Its totient is φ = 129175013088.
The previous prime is 131132210317. The next prime is 131132210347. The reversal of 131132210323 is 323012231131.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 323012231131 = 45943 ⋅7030717.
It is a cyclic number.
It is not a de Polignac number, because 131132210323 - 217 = 131132079251 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 131132210294 and 131132210303.
It is not an unprimeable number, because it can be changed into a prime (131132210023) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 978598518 + ... + 978598651.
It is an arithmetic number, because the mean of its divisors is an integer number (33272351890).
Almost surely, 2131132210323 is an apocalyptic number.
131132210323 is a deficient number, since it is larger than the sum of its proper divisors (1957197237).
131132210323 is an equidigital number, since it uses as much as digits as its factorization.
131132210323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1957197236.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 131132210323 its reverse (323012231131), we get a palindrome (454144441454).
The spelling of 131132210323 in words is "one hundred thirty-one billion, one hundred thirty-two million, two hundred ten thousand, three hundred twenty-three".
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