131132221121001 has 4 divisors (see below), whose sum is σ = 174842961494672. Its totient is φ = 87421480747332.

The previous prime is 131132221120991. The next prime is 131132221121003. The reversal of 131132221121001 is 100121122231131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 131132221121001 - 2¹⁵ = 131132221088233 is a prime.

It is a super-2 number, since 2×131132221121001² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (131132221121003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21855370186831 + ... + 21855370186836.

It is an arithmetic number, because the mean of its divisors is an integer number (43710740373668).

Almost surely, 2^{131132221121001} is an apocalyptic number.

It is an amenable number.

131132221121001 is a deficient number, since it is larger than the sum of its proper divisors (43710740373671).

131132221121001 is an equidigital number, since it uses as much as digits as its factorization.

131132221121001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43710740373670.

The product of its (nonzero) digits is 144, while the sum is 21.

Adding to 131132221121001 its reverse (100121122231131), we get a palindrome (231253343352132).

The spelling of 131132221121001 in words is "one hundred thirty-one trillion, one hundred thirty-two billion, two hundred twenty-one million, one hundred twenty-one thousand, one".