1311322400121 has 4 divisors (see below), whose sum is σ = 1748429866832. Its totient is φ = 874214933412.

The previous prime is 1311322400119. The next prime is 1311322400149. The reversal of 1311322400121 is 1210042231131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1311322400121 - 2¹ = 1311322400119 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1311322400111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218553733351 + ... + 218553733356.

It is an arithmetic number, because the mean of its divisors is an integer number (437107466708).

Almost surely, 2^{1311322400121} is an apocalyptic number.

It is an amenable number.

1311322400121 is a deficient number, since it is larger than the sum of its proper divisors (437107466711).

1311322400121 is an equidigital number, since it uses as much as digits as its factorization.

1311322400121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 437107466710.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 1311322400121 its reverse (1210042231131), we get a palindrome (2521364631252).

The spelling of 1311322400121 in words is "one trillion, three hundred eleven billion, three hundred twenty-two million, four hundred thousand, one hundred twenty-one".