13113230000003 has 4 divisors (see below), whose sum is σ = 14986548571440. Its totient is φ = 11239911428568.

The previous prime is 13113229999997. The next prime is 13113230000011. The reversal of 13113230000003 is 30000003231131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13113230000003 - 2²² = 13113225805699 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13113230000033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 936659285708 + ... + 936659285721.

It is an arithmetic number, because the mean of its divisors is an integer number (3746637142860).

Almost surely, 2^{13113230000003} is an apocalyptic number.

13113230000003 is a deficient number, since it is larger than the sum of its proper divisors (1873318571437).

13113230000003 is an equidigital number, since it uses as much as digits as its factorization.

13113230000003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1873318571436.

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 13113230000003 its reverse (30000003231131), we get a palindrome (43113233231134).

The spelling of 13113230000003 in words is "thirteen trillion, one hundred thirteen billion, two hundred thirty million, three", and thus it is an aban number.